Answer:
1 3/8
Step-by-step explanation:
3 2/3 = 11/3
2 2/3 = 8/3
11/3 / 8/3 = 11/3*3/8 = 11/8 = 1 3/8
Answer: a. Area b. 4222.26
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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A bicyclist travels at a constant speed of 12 miles per hour for a total of 45 minutes.
We know the formula , Distance = speed * time
Speed is constant and it is 12. So it is linear
The function becomes d = 12t, x is the t is the time and d is the distance
At the starting point, t=0 and distance d=0
End point , t=45 min = 0.75 hours and distance = 12 * 0.75 = 9
So domain (t) is {
}
Range (d) is {
}
Length x width is the formula.
so 18 x 18 for 7.
22 x 24 for 8.
and 8 would probably be 5 x 5 to equal 20. so the length and width would be 5 and 5 because 20 is the area
