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son4ous [18]
4 years ago
8

5.

Mathematics
1 answer:
kari74 [83]4 years ago
3 0

The length of the vector <-4,-3> is

\sqrt{(-4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5

So, if we divide the components by 5, we'll get a vector with unitary length:

v=\left(-\dfrac{4}{5}, -\dfrac{3}{5}\right) \implies |v| = \sqrt{\left(-\dfrac{4}{5}\right)^2+\left(-\dfrac{3}{5}\right)^2}=\sqrt{\dfrac{16}{25}+\dfrac{9}{25}}=\sqrt{\dfrac{25}{25}}=1

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