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larisa [96]
3 years ago
14

If ad= 20 and ac=3x+4,find the value of x.

Mathematics
1 answer:
Anna [14]3 years ago
6 0

We have AD =  DC

Thus, AC  = AD + AD = 20 + 20 = 40

We have:

3x + 4 =  40

3x =  40 - 4

3x =  36

x =  36 / 3

x =  12

AD= 20

AC= 40

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Answer:

The value of the given expression is

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Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

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=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

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=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

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Then solve for x

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