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Paul [167]
3 years ago
14

Quadrilaterals that are neither a trapezoid nor a rectangle?

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0
Square, rhombus, kite
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Solve for x<br> Show work
SashulF [63]

Answer:

x = 7

Step-by-step explanation:

123 = 17x + 4

123 - 4 = 17x

119 = 17x

119 / 17 = x

7 = x

3 0
3 years ago
Need help on answering 20.
Reptile [31]
N=64.
32+64=100
64/8=8
sqrt (64+225)= sqrt (289) = positive and negative 17
8 0
3 years ago
Answer this correct and you are a true legend 9 + 10 = ? ...
S_A_V [24]

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AcORdinG To MY CaLCulAtIoNS ItS 21

Step-by-step explanation:

Logic :)

5 0
3 years ago
Solve each system by substitution
anyanavicka [17]

Answer:

equalize the both sides of the functions

Step-by-step explanation:

4x-5 = 2x-5

4x = 2x

2x = x

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there is no answer for this problem

7 0
3 years ago
Read 2 more answers
Given a leading coefficient of 8, polynomial roots of 1 &amp; 2, and the known point on the graph (4,5). Write an equation that
m_a_m_a [10]

Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

y=a(x-c_1)(x-c_2)...(x-c_n)

Where, a is a constant and c_1,c_2,...,c_n are the roots of the polynomial.

Polynomial roots are 1 and 2. So, (x-1) and (x-2) are the factors of the polynomial.

Let the third root of the polynomial by c, then (x-c) is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

y=8(x-1)(x-2)(x-c)

The graph passes through the point (4,5). Putting x=4,y=5, we get

5=8(4-1)(4-2)(4-c)

5=8(3)(2)(4-c)

5=48(4-c)

Divide both sides by 48.

\dfrac{5}{48}=4-c

c=4-\dfrac{5}{48}

c=\dfrac{192-5}{48}

c=\dfrac{187}{48}

Therefore, the 3rd root on the polynomial is \dfrac{187}{48}.

8 0
3 years ago
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