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Liono4ka [1.6K]

3 years ago

12

A family took a trip. They spent $90.71 for gasoline, $153.00 on meals, $197.00 on amusements, and $73.38 on miscellaneous expen

ses. How much did the trip cost? $

2 answers:

MA_775_DIABLO [31]3 years ago

6 0

The correct answers is 414.09

Pachacha [2.7K]3 years ago

3 0

They spent $514.09 on the trip.
90.71 + 153.00 + 197.00 + 73.38 = $514.09

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Answer:

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And we can find the individual probabilities using the probability mass function

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And replacing we got:

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Step-by-step explanation:

Previous concepts

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Solution to the problem

Let X the random variable of interest "number of automobiles with both headligths working", on this case we now that:

$X \sim Binom(n=8, p=0.9)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

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And for this case we want to find this probability:

$P(X \geq 7) = P(X=7) +P(X=8)$

And we can find the individual probabilities using the probability mass function

$P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826$

$P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305$

And replacing we got:

$P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131$

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