Answer:
10 days
Step-by-step explanation:
It will take 10 men 5 days to dig a hole half as big.
It will take 5 men 10 days to dig a hole half as big.
( Remember, the less people, the more time it will take. )
100: 48400
1000:4800
10000:50000
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
Correct option is (C).
The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
Step-by-step explanation:
The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.
The <em>p</em> value of a test is:
Left-tailed test:
Right-tailed test:
.
Here,
TS = Test statistic
ts = computed value of the test statistic.
The two-tailed <em>p</em>-value is:
or
.
The <em>p</em>-value of the two tailed test is, 0.44.
Compute the <em>p</em>-value for one-tailed test a follows:


Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
The correct option is (C).
She plans to continue working in her position for an ... years. If she continues to earn a 2% increase in her annual ... The expression 1.02^(4+n) can be used because 1.02^4 ...
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