A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say
x.
The lateral faces are equilateral triangles of side length
x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find
x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:

thus,

thus:

(cm^2)
but

is exactly the base area, since the base is a square of sidelength =
x cm.
So, the total surface area = base area + lateral area =

cm^2
Answer:

cm^2
Answer:
c=26
Step-by-step explanation:
By using pythagoram thoerem
c^2=a^2+b^2
c^2=(10)^2+(24)^2
c^2=100+576
c^2=676
c=sqrt(676)
c=26
c=26
Answer:
B. 4
Step-by-step explanation:
The maximum number of teams the teacher can divide the class into is 4. I got it right on ED2020.
Answer:
what they currently going over?
Answer:
Step-by-step explanation:
This is a geometric sequence; we know that because of the words "common ratio." The general formula for a geometric sequence is
a(n) = a(1)*r^(n - 1), where r is the common ratio.
Here, a(1) = 1, r = 1/3, and so
a(1) = 1 (given)
a(2) = 1/3 (this is a(1) multiplied by 1/3)
a(3) = 1/9 (this is a(2) multiplied by 1/3)
a(4) = 1/27
a(5) = 1/81