Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Is it the area of the whole figure or the shaded part
Answer:
Step-by-step explanation:
6/4=(6-1)/(4-x)
6/4=5/(4-x)
6(4-x)=4(5)
24-6x=20
-6x=-4
x=4/6
x=2/3
2/3 of an inch should be cut off the width.
Answer:
26x-67-x²
Step-by-step explanation:
We are given
Expanding (x-8)²=x²-16x+64
10x-3-(x²-16x+64)
10x-3-x²+16x-64
26x-67-x²
1/5(25-5a)=4-a
⇔5-a=4-a
<span>NO SOLUTION</span>
