All categories

3 years ago

It has 3 more vertices than a triangle

Mathematics

2 answers:

vovikov84 [41]3 years ago

6 0

Well, a triangle has 3 vertices, and 3 + 3 would be 6 vertices. So it is a hexagon.

o-na [289]3 years ago

4 0

The answer would be a hexagon.

A vertice is simple a corner of a shape. A triangle has 3 corners, so it has three vertices. A hexagon has 6 corners, so it had 6 vertices!

You might be interested in

7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)

artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0

2 years ago

If f(x) = -x^3 + 2x^2 - 3, find f(2). A) -19 B) -3 C) -1 D) 5

AfilCa [17]

Answer:

Step-by-step explanation:

To evaluate f(2) substitute x = 2 into f(x), that is

f(2) = - (2)³ + 2(2)² - 3 = - 8 +2(4) - 3 = - 8 + 8 - 3 = - 3

7 0

2 years ago

Find the area of the figure.

andrezito [222]

Answer:

area of figure = area of rectangle + area of triangle

area of rectangle= length × width

6×4

24yd²

area of triangle= 1/2×base×height

1/2×3×4

3×2

=6yd²

area of figure= 24+6

= 30yd²

7 0

2 years ago

The diameter of a parabolic mirror is 22 centimeters, and the mirror has a depth of 0.5 centimeters at the center. What is the e

a_sh-v [17]

1/242x^2 is your answer

6 0

2 years ago

Graph the system of equations. {8x+8y=642x−2y=−4

klemol [59]

The graph is attached.

Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.

x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.

For the first equation, we would have
8x+8(0)=64
8x=64.

Divide both sides by 8:
8x/8 = 64/8
x=8.

For the second equation,
2x-2(0)=-4
2x=-4.

Divide both sides by 2:
2x/2 = -4/2
x=-2.

y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.

For the first equation,
8(0)+8y=64
8y=64.

Divide both sides by 8:
8y/8 = 64/8
y=8.

For the second equation,
2(0)-2y=-4
-2y=-4.

Divide both sides by -2:
-2y/-2 = -4/-2
y=2.

Plot these points for both equations and connect them to draw the line.

6 0

3 years ago