Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer:
See attached.
Step-by-step explanation:
Answer:
try math papa
Step-by-step explanation:
Divide the perimeter by 3 to find the side length.
Since the formula for the are of a triangle is
1/2 * b * h the height must be found.
If a perpendicular line is drawn from the apex of the triangle, a right triangle is formed with a base of 5 and a hypotenuse of 10. Also since it originally was equilateral the base angle is 60 degrees. The rules for finding lengths of sides of equal. Triangles is long leg = sqrt3 * short leg
the height is the long leg so the height is 5sqrt3.
A=(1/2)(10)(5sqrt3)= 25sqrt3
1728 inches hope this helps!
