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2 years ago

13

A sandwich shop has four types of sandwiches: ham, turkey, chicken, and PB&J.

1 answer:

dmitriy555 [2]2 years ago

3 0

Answer:

4

Step-by-step explanation:

each sandwich can be made on either white or whole grain. since there are only 4 options for sandwiches there are only 8 choices in total. ham w white or ham w grain, turkey w white turkey w grain, etc. so there is a probabilty of 4. let me know if im right!

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Below is a table for f(x) = 3x + 1. Using the table, determine the value of x when f(x) = 13

Elena L [17]

3x+1=13
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A. 792 432,795<br> What is 432,795 divided by 792

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Triangle ABC has angle measures as shown A x-5 B 3x+30 C 35 qhat is the value x

Vinvika [58]

Answer:

$x=30\ degrees$

$m$

$m$

Step-by-step explanation:

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2. A stone is an English measure of weight. There are 14 lb in 1 stone and 2.2 lb in 1 kg. A certain person weighs 9 stone. (a)

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Multiply the person's weight (9 stone) by the conversion factors (14 lb / 1 stone) and (1 kg / 2.2 lb). Please show your work.

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The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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2 years ago