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devlian [24]
3 years ago
13

Solve the inequality |8x + 4| <28 need answered fast!!!

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

The absolute value |x| always returns the "positive version" of a number.

This means that if the number is positive, the absolute value does nothing:

|x| = x

And if the number is negative, the absolute value flips its sign:

|x| = -x

So, if 8x+4 is positive, the inequality becomes

8x+4 < 28

If 8x+4 is negative, the inequality becomes

-8x-4 < 28 \iff 8x+4 > -28

So, 8x+4 must be either a positive number smaller than 28, or a negative number greater than -28. It means that

-28 < 8x+4 < 28

Subtract 4 from all sides:

-32 < 8x < 24

Divide all sides by 8:

-4 < x < 3

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Solve: 3|x+1|≥−6. Write your solution in interval notation
Lynna [10]

Answer:

3x+3 menor igual a -6

3x menor igual a -6-3

3x menor igual a -9

x es menor igual a -3

x es -2,-1,0,1,2,3,.......

Step-by-step explanation:

7 0
3 years ago
A sample contains information on 100 people. Forty-five percent of these people identify as English Language Learners, and the r
laiz [17]

Answer:

The proportion of English Learners is 45%

Step-by-step explanation:

Hello!

You have a sample of n=100 english speakers from wich 45 percent are English Language Learners and the rest Native english Speakers.

In proportions

n= 100 makes 100% english speakers

45% are English Language Learners

and

100% - 45%= 55% are Native English Speakers.

The answer is 45% is English Language Learners.

I hope you have a SUPER day!

4 0
4 years ago
Suppose 244 subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.01 significance
vodka [1.7K]

Answer:

z=\frac{0.209 -0.2}{\sqrt{\frac{0.2(1-0.2)}{244}}}=0.351  

p_v =P(z>0.351)=0.363  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of subjects with nauseas is not higher than 0.2 or 20% at 1% of significance.

Step-by-step explanation:

Data given and notation  

n=244 represent the random sample taken

X=51 represent the subjects with nausea

\hat p=\frac{51}{244}=0.209 estimated proportion of subjects with nausea

p_o=0.2 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.2.:  

Null hypothesis:p \leq 0.2  

Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.209 -0.2}{\sqrt{\frac{0.2(1-0.2)}{244}}}=0.351  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>0.351)=0.363  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of subjects with nauseas is not higher than 0.2 or 20% at 1% of significance.

6 0
3 years ago
Read 2 more answers
Can someone PLEASE tell me the answer to this
Yuki888 [10]

Answer: b

Step-by-step explanation: hope this helps

6 0
3 years ago
Which expression is equivalent to 5 (3+4)?<br> A) 15 + 20<br> B) 15 + 4<br> © 8 + 9<br> D) 15 + 9
insens350 [35]

Answer:

15 + 20

Step-by-step explanation:

if it is correct then please mark as a brainlist

7 0
3 years ago
Read 2 more answers
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