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Dmitrij [34]
3 years ago
8

Which is greater 1 millennium or 10 centuries?

Mathematics
2 answers:
elena-s [515]3 years ago
8 0
1 millennium cause centuries is a 100 years millennium is 1001 years so it is not centuries
Bingel [31]3 years ago
3 0
They are both the same
1 millenium - 1000 yrs
1 century -100 yrs
100 x 10 - 1000yrs
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Write each exponential function. <br>​
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Find the value of x, y, and z in the rhombus below.
34kurt

Answer:

Step-by-step explanation:

For a rhombus, the opposite angles are equal:

74=5y+9

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For a rhombus, the adjacent angles are supplementary:

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2 years ago
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Name a polygon that would have a
liubo4ka [24]

Answer:

The polygon has 43 sides . The polygon can be called 43 - gon or tetracontakaitrigon.

Step-by-step explanation:

In a regular polygon all the sides are equal and also all the angles are equal. The sum of the interior angle of a polygon can be calculated with the following formula;

sum of interior angle = (n−2) × 180°

where

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The sum of the interior angle should be less than 7500 and greater than 7201.

sum of interior angle = (n−2) × 180°

less than 7500 and greater than 7201 = (43 - 2) × 180

less than 7500 and greater than 7201 = 41 × 180

less than 7500 and greater than 7201 = 7380 °

The polygon has 43 sides . The polygon can be called 43 - gon or tetracontakaitrigon.

3 0
3 years ago
What is the slope of the line on the graph below? On a coordinate plane, a line goes through points (negative 2, negative 3), (n
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Answer:

2

Step-by-step explanation:

We can use 2 points to find the slope

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7 0
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Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

3 0
3 years ago
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