Answer:
En 2001 el pueblo poseía 45.826 habitantes.
Step-by-step explanation:
Un pueblo tenía 13.578 habitantes en 1970. En 1988 la población se incrementó 1,5 veces con respecto a 1970. Para calcular entonces la población en 1988 debes realizar el siguiente cálculo:
13.578*1,5= 20.367
Por lo que en 1988 el pueblo poseía 20.367 habitantes.
En 2001 se incrementó la población 2,25 veces en relación a 1988. Para calcular entonces la población en 2001 debes realizar el siguiente cálculo:
20.367* 2,25= 45.825,75≅ 45.826
Por lo que <u><em>en 2001 el pueblo poseía 45.826 habitantes.</em></u>
Answer:
The initial population was 2810
The bacterial population after 5 hours will be 92335548
Step-by-step explanation:
The bacterial population growth formula is:

where P is the population after time t,
is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours
Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:





Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:



Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:


Answer : The cost of 10 balls will be, 13.5 dollars
Step-by-step explanation :
As we are given the following expression:

where,
P = total price (in dollars)
n = number of balls used
Given:
n = number of balls used = 10
Now we have to determine the cost of 10 balls.




Thus, the cost of 10 balls will be, 13.5 dollars
Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1
f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
Answer:
64 times 4 and add the x at the end = 256x
Step-by-step explanation: