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Setler [38]
3 years ago
10

A building 50 ft high casts a 75-ft shadow. Sarah casts a 6-ft shadow. The triangle formed by the building and its shadow is sim

ilar to the triangle formed by Sarah and her shadow. How tall is Sarah?
Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0
Make each known side into a ratio like so...
75/6 
(Because 75 is the shadow casted by the building, and 6 is the shadow casted by sarah)
and 50/x 
(50 is how tall the building is and sarah's height is what needs to be found) 
Therefore, 
75    50
----  -----
 6      x

Do cross products;
50 x 6 = 75 x X
300 = 75x 
Divide by 75 
x = 4ft

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Un pueblo tenía 13.578 habitantes en 1970. En 1988 la población se incrementó 1,5 veces con respecto a 1970 y en 2001 se increme
igor_vitrenko [27]

Answer:

En 2001 el pueblo poseía 45.826 habitantes.

Step-by-step explanation:

Un pueblo tenía 13.578 habitantes en 1970. En 1988 la población se incrementó 1,5 veces con respecto a 1970. Para calcular entonces la población en 1988 debes realizar el siguiente cálculo:

13.578*1,5= 20.367

Por lo que en 1988 el pueblo poseía 20.367 habitantes.

En 2001 se incrementó la población 2,25 veces en relación a 1988. Para calcular entonces la población en 2001 debes realizar el siguiente cálculo:

20.367* 2,25= 45.825,75≅ 45.826

Por lo que <u><em>en 2001 el pueblo poseía 45.826 habitantes.</em></u>

8 0
2 years ago
The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000
Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

P = P_0 \times e^{rt}

where P is the population after time t, P_0 is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

2 P_0 = P_0 \times e^{r 1/3}

2 = e^{r \; 1/3}

ln 2 = r \; 1/3

ln 2 \times 3 = r

2.08 \% = r

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

90000 = P_0 \times e^{2.08 \; 5/3}

\frac{9000}{e^{2.08 \; 5/3}} = P_0

2810 = P_0

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

P = 2810 \times e^{2.08 \; 5}

P = 92335548

3 0
3 years ago
A paintball court charges an initial entrance fee plus a fixed price per ball.
m_a_m_a [10]

Answer : The cost of 10 balls will be, 13.5 dollars

Step-by-step explanation :

As we are given the following expression:

P=0.80\times n+5.50

where,

P = total price (in dollars)

n = number of balls used

Given:

n = number of balls used = 10

Now we have to determine the cost of 10 balls.

P=0.80\times n+5.50

P=0.80\times (10)+5.50

P=8+5.50

P=13.5\$

Thus, the cost of 10 balls will be, 13.5 dollars

4 0
3 years ago
Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1
MaRussiya [10]
Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1

f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
3 0
3 years ago
Read 2 more answers
How do I find the variables here? ;-;
ELEN [110]

Answer:

64 times 4 and add the x at the end  = 256x

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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