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kiruha [24]
2 years ago
11

5/7 - 3/2 in simplest form HELP ASAP

Mathematics
2 answers:
ohaa [14]2 years ago
5 0

\boldsymbol{\sf{\dfrac{5}{7}-\dfrac{3}{2}  }}

The least common multiple of 7 and 2 is 14. Convert 5/7 and 3/2 to fractions with like denominators.

\boldsymbol{\sf{ \dfrac{5\times2}{7\times2}-\dfrac{3\times7}{2\times7} \ \ \to \ \ \ Simplify }}

\boldsymbol{\sf{\dfrac{10}{14}-\dfrac{21}{14}   }}

Since 10/14 and 21/14 have the same denominator, subtract their numerators to subtract them.

\boldsymbol{\sf{\dfrac{10-21}{14} \ \ \to \ \ \ Subtract}}

Subtract 21 from 10 to get −11.

\red{\boxed{\boldsymbol{\sf{-\frac{11}{14} }}}} \ \ \to \ \ \boldsymbol{\sf{Answer}}

<h2>{ Pisces04 }</h2>
IgorC [24]2 years ago
4 0

\frac{5}{7}  \:  -  \:  \frac{3}{2}

  • First, we find the <u>lowest common denominator</u> which is "14", we put it in the common numerator.

\frac{10 \:  -  \: 21}{14}

  • We subtract the numbers.

\boxed{ \bold{- \frac{11}{14} }}

<h3><em><u>MissSpanish</u></em></h3>
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Cerrena [4.2K]

Answer:

180 - 172 =$8 8/3=2.56

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3 years ago
The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 intersect to form the sides of a right triangle. Find the perimeter and area
tino4ka555 [31]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Determining the perimeter and area of the triangle giving line equation</h3>

In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

The points of intersection of the line are;

(x₁, y₁) = (- 0.4, 5.2),

(x₂, y₂) = (-0.8, 4.4),

(x₃, y₃) = (0, 4)

Determine the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

Determine the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/12010318

#SPJ1

3 0
1 year ago
Using the diagram above,what is the m
makkiz [27]
I’m pretty sure the angle in 53 degrees
4 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
Which geometric series converges ???
ki77a [65]

Answer:

C

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sum to infinity = \frac{a}{1-r}

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a_{n} = ar^{n-1}

where a is the first term and r the common ratio

The only summation with - 1 < r < 1 is C where r = - 0.2

7 0
3 years ago
Read 2 more answers
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