Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by: c^2=a^2+b^2 where: c is the hypotenuse a and b are the legs. c=10 a=6 b=(x-6) thus plugging the values in the equation and solving for x we get: 10^2=6^2+(x-6)^2 100=36+x^2-12x+36 100=x^2-12x+72 0=x^2-12x-28 factoring the above we get: 0=(x+2)(x-14) hence x=-2 or x=14 given that there is no negative distance then x=14 thus the value of x is 14
