<span>The best answer to this problem is 0.0823.
np = 48 * 1/4 = 12
The exactly 15 would be written as 14.5 to 15.5. You then plug those into you equation separately.
e1= (14.5-12)/3 = 0.833 and e2 =(15.5 - 12)/3 = 1.167)
p(0.833<e<1.167)= 0.0808</span>
Answer:
cheat off somebody who has the answer
Step-by-step explanation:
Answer:
the answer for this one is A
Step-by-step explanation:
mostly because for this you're only looking for H and not the rest of them so if you reflect is itll be in the same spot just on the opposite side
The amount of water that has entered the pool over these five minutes is 42.5 gallons.
Given the rate at which water enter the pool W(t). To calculate the amount of water that has entered the pool over these five minutes, we integrate W(t) over the interval t = 0 to t = 5.
![Amount\ of \ water=\int\limits^0_5 {W(t)} \, dt \\\\\\Amount\ of \ water=\int\limits^0_5 {(1+3t)} \, dt \\\\\\Amount\ of \ water=[t+1.5t^2]_0^5\\\\\\Amount\ of \ water=42.5\ gallons](https://tex.z-dn.net/?f=Amount%5C%20of%20%5C%20water%3D%5Cint%5Climits%5E0_5%20%7BW%28t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D%5Cint%5Climits%5E0_5%20%7B%281%2B3t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D%5Bt%2B1.5t%5E2%5D_0%5E5%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D42.5%5C%20gallons)
The amount of water that has entered the pool over these five minutes is 42.5 gallons.
Find out more on integration at: brainly.com/question/23976638
Answer:
226?
Step-by-step explanation: