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2 years ago

Find the equation of a line that passes through these two points

Mathematics

2 answers:

Sati [7]2 years ago

6 0

Answer:

y = -2x + 2

Step-by-step explanation:

The equation of a line is y = mx + b.

First we want to find m, the slope. We can used the coordinates to do so: $m = \frac{6-(-4)}{-2-3}\\m = \frac{10}{-5}\\m = -2$

Now we know that the equation is y = -2x + b. We can plug in the coordinate (3, -4) to find b.

$y = -2x + b\\-4 = -2(3) + b\\-4 = -6 + b\\b = 2$

So the equation is y = -2x + 2.

weeeeeb [17]2 years ago

5 0

Answer:y=-2x+2

Step-by-step explanation:First enter your points in this equation y2-y1/x2-x1

6-(-4)/-2-3)=10/-5=-2

Then find your y intercept. Choose whatever point but I’m choosing the first one. (3,-4) Plug into y=mx+b

-4=-2(3)+b

-4=-6+b

add 6 to both sides

2=b

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According to a Pew Research Center study, in May 2011, 35% of all American adults had a smart phone (one which the user can use

taurus [48]

Answer:

$z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82$

$p_v =P(z>1.82)=0.034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis

And the best conclusion would be:

There is enough evidence to show that more than 35% of community college students own a smart phone (Pvalue = 0.034).

And for the second case the correct system of hypothesis is:

H0: p = 0.078; Ha: p > 0.078

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

$\hat p=\frac{120}{300}=0.4$ estimated proportion of college students that have a smart phone

$p_o=0.35$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is >0.35.:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.82)=0.034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis

And the best conclusion would be:

There is enough evidence to show that more than 35% of community college students own a smart phone (Pvalue = 0.034).

And for the second case the correct system of hypothesis is:

H0: p = 0.078; Ha: p > 0.078

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3 years ago

Thuy has $625 in her checking account she writes two checks for $23 each and then makes one deposit of $146 what is thuy’s final

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3 years ago

Read 2 more answers