Question

Find the equation of a line that passes through these two points

Answer 1

Answer:

y = -2x + 2

Step-by-step explanation:

The equation of a line is y = mx + b.

First we want to find m, the slope. We can used the coordinates to do so: $m = \frac{6-(-4)}{-2-3}\\m = \frac{10}{-5}\\m = -2$

Now we know that the equation is y = -2x + b. We can plug in the coordinate (3, -4) to find b.

$y = -2x + b\\-4 = -2(3) + b\\-4 = -6 + b\\b = 2$

So the equation is y = -2x + 2.

Answer 2

Answer:y=-2x+2

Step-by-step explanation:First enter your points in this equation y2-y1/x2-x1

6-(-4)/-2-3)=10/-5=-2

Then find your y intercept. Choose whatever point but I’m choosing the first one. (3,-4) Plug into y=mx+b

-4=-2(3)+b

-4=-6+b

add 6 to both sides

2=b