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Karo-lina-s [1.5K]
3 years ago
13

What is the distance between (-4,6) and (3,-7)

Mathematics
1 answer:
melomori [17]3 years ago
6 0
(-7 , 13) is the distance
You might be interested in
3\10 x 2\3<br><br> A.5\30<br><br><br> B.6\13<br><br><br> C.1\5<br><br><br> D.5\13
kow [346]
3/10 times 2/3 3 times 2 is 5 and 10 times 3 is 30 5/30 a
3 0
3 years ago
Read 2 more answers
7/10 of 120 and show work pls
slavikrds [6]
When it says 7/10, it actually means 70%, so you have to find 70% of 120.
<span>
70 % of 120 
= 70% x 120 
= (70/100) x 120 
= (8400/100) 
= 84

Answer: 84</span>
8 0
3 years ago
Please explain how you got this answer.
Tema [17]
150 times

out of the first 5 cards, there is a 3/5 chance of drawing a yellow.
if you replace the card and draw again, you still have a 3/5 chance of drawing a yellow card.
keep doing this process for 250 draws, each draw will always have 3/5 chance of drawing a yellow card.

so 3/5 +3/5 +3/5 +...  (250 times) = 250 x 3/5 = 150

3 0
3 years ago
-25 Points-
Over [174]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{8}}{\sqrt[3]{125}}\implies \cfrac{s}{s}=\cfrac{2}{5}\qquad \leftarrow \textit{ratio of the sides or scale factor}

8 0
3 years ago
The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
3 years ago
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