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Readme [11.4K]
2 years ago
7

Please help me solve this problem. Whoever answers right first will be brainliest

Mathematics
1 answer:
Phantasy [73]2 years ago
5 0

Answer:

100 waffles

Step-by-step explanation:

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Find the equation of the line. use exact numbers.
svp [43]

Answer:

y=4x -9

Step-by-step explanation:

y intercept- where the line crosses the y-axis (-9)

Rise over run- 4

6 0
2 years ago
If a 10-foot piece of electrical tape has five pieces that are each 1.25 feet cut from it, what is the new length of the tape?
BartSMP [9]
5 pieces X 1.25 = 6.25

10-6.25 = 3.75 is the new length
3 0
3 years ago
Please help if you can :)
crimeas [40]

The graph is Parabola or Graph of Quadratic Function.

The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.

B is not correct for exponential part.

also C is not correct for discrete part as Quadratic graph is continuous.

So the answer is D.

7 0
2 years ago
Integration of (cosec^2 x-2005)÷cos^2005 x dx is
kondor19780726 [428]
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then, 
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
7 0
2 years ago
Find the surface area of the right prism. Round to the nearest whole number.
andriy [413]

Answer:

\large\boxed{S.A.=96\ cm^2}

Step-by-step explanation:

We have:

(1) two trapezoids with bases b₁ = 7cm and b₂ = 5cm and the height h = 4cm

(2) three rectangles 3 cm × 7 cm, 3 cm × 4 cm and 3 cm × 5 cm.

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A=\dfrac{7+5}{2}\cdot4=24\ cm^2

Calculate the areas of the rectangles:

A_1=(3)(7)=21\ cm^2\\\\A_2=(3)(4)=12\ cm^2\\\\A_3=(3)(5)=15\ cm^2

The Surface Area:

S.A.=(2)(24)+21+12+15=96\ cm^2

5 0
2 years ago
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