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Ksju [112]
3 years ago
7

Help please, thanks :)

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

60°

Step-by-step explanation:

Angle 1 is a vertical angle to 60° by the definition of a vertical angle.

andrew-mc [135]3 years ago
6 0

Answer:

∠1 = 60°

Step-by-step explanation:

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Maria found the least common multiple of 6 and 15. Her work is shown below.
Alex

The answer is D. Maria selected a multiple that is not the least of the common multiples.

We see from the list that the least common multiple between 6 and 15 is 30, not 60.

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3 years ago
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Even the 2 figures are similar what scale factor can be used upon the missing length X.
Papessa [141]
B) 1/2
It’s b if you do the work you will find that out
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F(x) = 3х + 2 and g(x) = X + 5<br> g[f(x)] =<br> A:Зx +7<br> B:3х + 17<br> C:4x +7
vitfil [10]

Answer:

Answer is A.. ( i.e. 3x + 7 )

4 0
3 years ago
What’s the answer please
skad [1K]

Answer:

h  ≤ 124 / 9

or

h  ≤ 13.78

Step-by-step explanation:

(3/4) (12h - 32) ≤ 100      (multiply both sides by 4)

(3) (12h - 32) ≤ 100 (4)

(3) (12h - 32) ≤ 400   (distribute 3 into the parenthesis)

(12h)(3) - (32)(3) ≤ 400   (expand left side terms)

36h - 96 ≤ 400   (add 96 to both sides)

36h  ≤ 400  + 96

36h  ≤ 496  (divide both sides by 36)

h  ≤ 496 / 36   (sinmplify)

h  ≤ 124 / 9

or

h  ≤ 13.78

3 0
3 years ago
Triangle ABC has vertices A(0,0) B(6,8) and C(8,4). Which equation represents the perpendicular bisected of BC?
AveGali [126]

Answer:

y = \frac{1}{2}x+\frac{5}{2}

Step-by-step explanation:

The perpendicular bisector of a line passes through the mid-point of the line and the product of slopes of the line and perpendicular bisector will be -1.

So,

Mid-point\ of\ BC = (\frac{6+8}{2},  \frac{8+4}{2})\\= (\frac{14}{2},  \frac{12}{2})\\= (7,6)

The line will pass through (7,6)

Now,

Slope\ of\ BC = m_1 = \frac{y_2-y_1}{x_2-x_1} \\=\frac{4-8}{8-6}\\= \frac{-4}{2}\\= -2

Let

m_2 be the slope of perpendicular bisector

So,

m_1*m_2 = -1

-2 * m_2 = -1

m_2 = -1/-2 = 1/2

The standard equation of line is:

y=mx+b

Where m is slope

So putting the value of slope and point to find the value of b

6 = \frac{1}{2}*7 +b\\ 6 = \frac{7}{2} + b\\b = 6 - \frac{7}{2}\\ b = \frac{12-7}{2}\\b = \frac{5}{2}\\So,\ the\ equation\ of\ perpendcular\ bisector\ of\ BC\ is:\\y = \frac{1}{2}x+\frac{5}{2}

..

7 0
3 years ago
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