Question

In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square units?

Answer 1

Look at the picture.

$A_\triangle=\dfrac{bh}{2}$

$b=7,\ h=4\\\\A_\triangle=\dfrac{7\cdot4}{2}=14$

Answer: D. 14 units²

Answer 2

Answer:

Option (D).

Step-by-step explanation:

AB=$\sqrt{(7-0)^{ ^{2}} +(3-3)^{2}$

AB=7 unit

BC=$\sqrt{(7-7)^{ ^{2}} +(7-3)^{2}$

BC=4 unit

Area of a triangle=$\frac{1}{2}$×base×height

Area of a triangle ABC=$\frac{1}{2}$×AB×BC

Area =$\frac{1}{2}$×7×4

Hence,Area of a triangle=14 $unit^{2}$