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NeTakaya
3 years ago
14

In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square unit

s?

Mathematics
2 answers:
lora16 [44]3 years ago
5 0

Look at the picture.

A_\triangle=\dfrac{bh}{2}

b=7,\ h=4\\\\A_\triangle=\dfrac{7\cdot4}{2}=14

Answer: D. 14 units²

Nookie1986 [14]3 years ago
3 0

Answer:

Option (D).

Step-by-step explanation:

AB=\sqrt{(7-0)^{ ^{2}} +(3-3)^{2}

AB=7 unit

BC=\sqrt{(7-7)^{ ^{2}} +(7-3)^{2}

BC=4 unit

Area of a triangle=\frac{1}{2}×base×height

Area of a triangle ABC=\frac{1}{2}×AB×BC

Area =\frac{1}{2}×7×4

Hence,Area of a triangle=14 unit^{2}

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If the radius of circle O is 10 inches and m∠UON=90∘, what is the area of sector URN⌢?
arsen [322]

Answer:

  75π in²

Step-by-step explanation:

The shaded sector is 3/4 of the circle. We can use the area formula for a circle to find the area of the whole circle, then multiply that result by 3/4.

  A = πr² = π(10 in)² = 100π in²

Then the area of 3/4 of the circle is ...

  3/4·A = (3/4)·100π in² = 75π in²

6 0
3 years ago
Express the solutions of −34 < x < 10 in three different ways. Which is the solution in interval notation?
Phantasy [73]

-34

5 0
3 years ago
Read 2 more answers
Part 1: Create a scenario for an arithmetic sequence. For example, Jasmine practices the piano for ______ minutes on Monday. Eve
mr Goodwill [35]
Let a_n be the n'th term of a sequence, 

for example a_1 is the first term, a_2 is the second term and so on.
----------------------------------------------------------------------------------------------------
a sequence is arithmetic if the difference between any 2 terms is equal:

so an arithmetic sequence, for the first term = t, and the common difference = d, has the following form:

a_1=t

a_2=t+d

a_3=t+d+d

a_4=t+d+d+d

so clearly a_n=t+d*(n-1)
---------------------------------------------------------------------------------------------------
A sequence is geometric, if the ratio between any 2 consecutive terms is the same, and it is called the common ratio.

a geometric ratio with first term = t, and common ratio = r is:

a_1=t

a_2=t*r

a_3=t*r*r

a_4=t*r*r*r

thus clearly a_n=t* r^{n-1}
--------------------------------------------------------------------------------------------------

Part 1:

"<span>Jasmine practices the piano for  __30___ minutes on Monday. Every day she ____increases_______ her practice time by ____5 minutes_____. </span>"


let a_n be the number of hours Jasmine practices the n'th day, 

for n=7, t=30, d=5 we have

a_7=30+5*(7-1)=30+5*6=30+30=60,
 
minutes is the time Jasmine practices on the 7the day.


Part 2

 "<span>Anthony goes to the gym for ___60___ minutes on Monday. Every day he ___increases______his gym time by ____1/10_of the previous day_____. </span>"

if S_n represents the minutes that Anthony goes to gym on the n'th day, 

then

S_1=60

S_2=60+1/10*60=10/10*60+1/10*60=11/10*60=1.1*60

S_3=1.1*1.1*60

S_4=1.1*1.1*1.1*60

S_5=1.1*1.1*1.1*1.1*60= (1.1)^{4}*60= 1.4641*60=87.85
 (minutes)

Part 3: it is clear that the formula that can be derived in Part 2 is:

S_n=60*(1.1)^{n-1}

so assume we want to find how many hours does Anthony spend in the gym on the 10th day,

then we calculate S_10=60*(1.1)^{9}=60*2.358=141.5  (minutes)





6 0
3 years ago
Please help me 15 points
Debora [2.8K]

Answer:

what I can't see clear pic

8 0
3 years ago
Read 2 more answers
Write an equation for the translation of y=3/x with asymptotes of x=7 and y=-5
Sergeeva-Olga [200]

Answer:

y = (3 / (x-7)) - 5

Step-by-step explanation:

The original equation has the asymptotes at x = 0 and y = 0.

We want to translate to the right by 7 units so that the asymptote is at x = 7 and downwards 5 units so that the asymptote is y = -5.

Now, in the first case, to move it to the right, you must subtract 7 from the independent variable (i.e. x)

And in the second case, to move a function down 5 units, subtract 5 units from the entire function.

Applying the above, the new function would be:

y = (3 / (x-7)) - 5

8 0
4 years ago
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