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tangare [24]
3 years ago
6

In a pen with rabbits and chickens someone counted 25 heads and 80 legs a rabbit has four legs and each chicken has 2 legs, how

many chickens and rabbits are there?
Mathematics
2 answers:
Basile [38]3 years ago
7 0
Let "rabbits" be represented by the variable "x"
and "chickens" be represented by the variable "y"

then in total we have 25 animals
so  x + y = 25
-> y = -x + 25
and since a rabbit has four legs and a chicken has two legs
and there are 80 legs in total
4x + 2y = 80
-> 2x + y = 40
-> y = -2x + 40

[I had solved for y for each equation]
and since we are looking for when  y = y
-x + 25 = -2x + 40   [we can solve for x from here]
x + 25 = 40     [added 2x to both sides]
x = 15  [subtracted 25 from both sides]

then we can plug this back into
y = -x + 25
to get  y = -15 + 25 = 10

therefore there are 15 Rabbits and 10 Chickens
Komok [63]3 years ago
6 0
I just kind of sat here playing with numbers i dont really know a shortcut but the answer is 10 chickens and 15 rabbits 
10*2= 20 each chicken has two legs so thats 10 heads 20 legs
15*4=60 each rabbit has four legs so thats 15 heads 60 legs
15+10=25 heads
20+60=60 legs
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Step-by-step explanation:

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olganol [36]

6yd and 216in and both equal

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Which equations have infinitely many solutions?
igomit [66]

Answer:

4(x - 1) = 4x - 4

3x + 6 = 3(x + 2)

Step-by-step explanation:

The first equation is

5x - 1 = 5x + 1

We simplify to get;

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This is not true, therefore this equation has no solution.

The second equation is

3x - 1 = 1 - 3x

Combine like terms:

3x + 3x = 1 + 1

6x = 2

x =  \frac{1}{3}

This has a unique solution.

The 3rd equation is

7x - 2 = 2x - 7

Group similar terms:

7x - 2x =  7 + 2 \\ 5x = 9 \\ x  =  \frac{9}{5}

The 4th equation is :

4(x - 1) = 4x - 4

4x - 4= 4x - 4 \\ x = x

This is always true. The equation has infinite solution.

The 5th equation is:

3x + 6 = 3(x + 2) \\ 3x + 6 = 3x + 6 \\ x = x

This also has infinite solution

The 6th equation is

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8 0
3 years ago
What is the solution to the above system of equations?
kow [346]

(x , y) = (7, - 1)

2x + 3y = 11 → (1)

3x + 3y = 18 → (2)

subtracting (1) from (2) term by term eliminates the y- term

(3x - 2x) + (3y - 3y) = (18 - 11)

x + 0 = 7 ⇒ x = 7

substitute x = 7 into either of the 2 equations and solve for y

(1) → (2 × 7) + 3y = 11

14 + 3y = 11

subtract 14 from both sides

3y = 11 - 14 = - 3

divide both sides by 3

\frac{- 3}{3} = - 1

solution is (7 , -1)


8 0
3 years ago
Read 2 more answers
Find the sum of the polynomials. (3x3 + 4x2 - 2x + 1) + (x4 - x3 + 5x2 + 2x + 3) A. x4 + 2x3 + 9x2 - 4x + 4 B. x4 + 4x3 + 9x2 +
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