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2 years ago

I need to solve for X X=

Mathematics

1 answer:

Gemiola [76]2 years ago

6 0

$\dfrac{2\frac{1}{4}}{\frac{3}{8}}=\dfrac{\frac{15}{16}}{x}\ \ \ \ |\text{cross multiply}\\\\2\dfrac{1}{4}x=\dfrac{3}{8}\cdot\dfrac{15}{16}\\\\\dfrac{2\cdot4+1}{4}x=\dfrac{45}{128}\\\\\dfrac{9}{4}x=\dfrac{45}{128}\ \ \ \ \ |\text{multiply both sides by 4}\\\\9x=\dfrac{45}{32}\ \ \ \ \ |\text{divide both sides by 9}\\\\\boxed{x=\dfrac{5}{32}}$

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The pyramid shown has a square base that is 32 centimeters on each side. The slant height is 24 centimeters. What is the lateral

masya89 [10]

L.S.A.=1/2pl where p represents the perimeter of the base and l the slant height.
L.S.A. = ½(4*32)(24)
L.S.A. = ½ (128)(24)
L.S.A. =1/2(3072)
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2 years ago

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If a triangle has side lengths 7, 10, and 12, is it a right triangle??

Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, $a^2 + b^2 = c^2$

where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, $7^2 + b^2 = 12^2$ or $10^2 + b^2 = 12^2$

$7^2 + b^2 = 12^2$ ==> 49 + b^2 = 144 ==> b= $\sqrt{95$ ==> 9.746

b= 9.7, not 10.

$10^2 + b^2 = 12^2$ ==> 100 + b^2 = 144 ==> b = $\sqrt{44$ ==> 6.633 

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

Hope this helps!

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2 years ago

HELP!

Klio2033 [76]

It’s 50/50 hope this helps

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3 years ago

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Pani-rosa [81]

Answer:

A. 0.33

B.0.6

C.1.5

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