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4 years ago

How much will each fifth grader spend on lunch?

Mathematics

2 answers:

allsm [11]4 years ago

5 0

$3.50 each fifth grader will spend

Gwar [14]4 years ago

4 0

The answer is $3.50 because 315 divided by 90 equals 3.5.

You might be interested in

What percent of 800 is 712

zavuch27 [327]

Explanation for the problem:

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 712 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 712, so we can write it down as 100%=712.

4. We know, that x% equals 800 of the output value, so we can write it down as x%=800.

5. Now we have two simple equations:

1) 100%=712

2) x%=800

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=712/800

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 800 is what percent of 712

100%/x%=712/800

(100/x)*x=(712/800)*x - we multiply both sides of the equation by x

100=0.89*x - we divide both sides of the equation by (0.89) to get x

100/0.89=x

112.3595505618=x

x=112.3595505618

Answer:

800 is 112.3595505618% of 712

5 0

4 years ago

Read 2 more answers

What is the value of sinθ given that (3, −7) is a point on the terminal side of θ ? −758√58 758√58 358√58 −358√58?

Svetach [21]

Answer:

$\boxed{\sin(\theta)=-\frac{7}{58}\sqrt{58}}$

Step-by-step explanation

The given point $(3,-7)$ tells us that the terminal side of $\theta$ is in the fourth quadrant.

From the diagram in the attachment,

We can use the Pythagoras Theorem to find the length of the hypotenuse of the right triangle.

Let the hypotenuse be $h\: units$ . Then,

$h^2=7^2+3^2$

$h^2=49+9$

$h^2=58$

$\Rightarrow h=\sqrt{58}$

Now we use the sine ratio;

$\sin(\theta)=\frac{Opposite}{Hypotenuse}$ .

But since the terminal side of $\theta$ is in the fourth quadrant, the sine ratio must be negative.

This implies that;

$\sin(\theta)=-\frac{7}{\sqrt{58}}$ .

We rationalize the denominator to get;

$\sin(\theta)=-\frac{7}{58}\sqrt{58}$ .

3 0

3 years ago

The vertices of a square are A(–2, 4), B(4, 4), C(4, –2), and D(–2, –2). The diagonals of the square intersect at their midpoint

sertanlavr [38]

A(–2, 4), B(4, 4), C(4, –2), D(–2, –2)
-> select some diagonal: AC
midpoint is at A+(1/2)*AC

-> calculate vector AC:
AC=(4-(-2),-2-4)=(6,-6)
-> calculate half length of AC:
(1/2)*AC=(3,-3)

A+(1/2)*AC=
(-2,4)+(3,-3)=(1,1) which is the midpoint

so the first option is correct

4 0

3 years ago

Landen spent LL hours at the beach last weekend. Matéo spent 15\%15% fewer hours at the beach than Landen did. Which of the foll

ivanzaharov [21]

Answer: 0.85 L or $\frac{85L}{100}$ or $\frac{17L}{20}$