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3 years ago

How do you construct a regular polygon inside a circle?

1 answer:

7 0

You could use a ruler, think about how you want the polygon inside of the circle or how you want the circle to surround the polygon. When you use a ruler, make sure your co-ordinates inside of the circle are correct though before drawing the line.

I hope this info helps! :3

You might be interested in

3 & 5 please step by step

BlackZzzverrR [31]

Answer:

#3=51. #5=85

Step-by-step explanation:

#3. PEMDAS

(2-10×6)-7

PARENTHESIS FIRST

MULTIPLICATION FIRST

10×6=60

60-2=58

58-7=51

#5. PEMDAS

(12-11)+12×7

PARENTHESIS FIRST

12-11=1

1+12×7

MULTIPLICATION FIRST

12×7=84

84+1=85

4 0

3 years ago

How would I convert this function into an equation ?

vivado [14]

Definition

Functions have zeros or x-values that generate function values equal to zero.

Equations have roots or solutions that can be substituted into the polynomial in order to generate a value equal to zero.

Given:

$f(x)\text{ = -}\frac{1}{3}\sqrt[]{x}\text{ + 3}$

To convert this to an equation, we set f(x) equal to zero i.e

$f(x)\text{ = 0}$

The resulting equation is:

$-\text{ }\frac{1}{3}\sqrt[]{x}\text{ + 3 = 0}$

5 0

1 year ago

You suddenly realize that you do not like to add fractions. You ask your three best friends if they like to add fractions and th

Anettt [7]

The answer is B. deductive reasoning.

3 0

3 years ago

Solve for L. m=LN+2/K

Iteru [2.4K]

Answer:

$l = \frac{m - \frac{2}{k} }{n} \\ \\$

Step-by-step explanation:

$m = ln + \frac{2}{k} \\ m - \frac{2}{k} = ln \\ \frac{m - \frac{2}{k} }{n} = \frac{ln}{n} \\ l = \frac{m - \frac{2}{k} }{n} \\$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

4 years ago

Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am

Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

6 0

3 years ago