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3 years ago

How many x intercepts does the graph of y =|x-2|+12

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

Answer:

The graph not have x-intercepts

Step-by-step explanation:

we know that

The x-intercept is the value of x when the value of y is equal to zero

we have

$y=\left|x-2\right|+12$

This is the equation of an absolute value in vertex form open upward

The vertex is the point (2,12)

The y-coordinate of the vertex is above the x-axis and the graph open upward

That means ----> The graph do not intersect the x-axis

therefore

The graph not have x-intercepts

Verify

For y=0

substitute in the equation

$0=\left|x-2\right|+12$

$\left|x-2\right|=-12$ ----> is not true

The left side of the equation cannot be a negative number

The equation not have solution for y=0

therefore

The graph not have x-intercepts

see the attached figure to better understand the problem

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If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$