Explain how to break apart the addends to find the sum of 25 + 16

Find the 17th term in the sequence for which a1 = 10 and d = -3.

yKpoI14uk [10]

Answer:

d. -38

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is as follows:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

$a_{n} = a_{1} + (n-1)*d$

In this question:

$a_{1} = 10, d = -3$

17th term:

$a_{17} = a_{1} + (17-1)*d = 10 + 16*(-3) = -38$

So the correct answer is:

d. -38

6 0

3 years ago

Write a real world problem that compares 0.4 and 0.29. Then solve the problem.

ira [324]

Lizzy's new neckalce cost 0.4 cents less than lucy's neckalce that cost 0.29. cents.How many cents did lizzy's neckalce cost.

5 0

3 years ago

Read 2 more answers

What is the arc length of the arc sub tended in a circle with radius 6 and an angle of 7 pi/ 8

KengaRu [80]

Answer:

Formula for the Arc length is given by:

$\text{Arc length} = 2 \pi r \cdot \frac{\theta}{360^{\circ}}$

As per the statement:

radius of circle(r) = 6 units

Angle ( $\theta$ ) = $\frac{7 \pi}{8}$ radian

Use conversion:

$1 rad = \frac{180}{\pi}$

$\frac{7 \pi}{8}$ = $\frac{180}{\pi} \cdot \frac{7 \pi}{8} = \frac{1260}{8} = 157.5^{\circ}$

then;

substitute these given values we have;

Use value of $\pi = 3.14$

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot \frac{157.5^{\circ}}{360^{\circ}}$

or

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot 0.4375$

Simplify:

$\text{Arc length}=16.485$

Therefore, the arc length of the arc substended in a circle with radius 6 units an angle of 7 pi/8 is 16.485 units

7 0

3 years ago

PLEASE HURRY<br> How do i solve these problems

Tatiana [17]

Answer:

X = 13

X = 70

Step-by-step explanation:

1. Since it is a right angle set the equation up as X +2 + 75 = 90.

X =13

2. Set up x - 20 + 40 = 90 since right triangles are 90 degrees

x = 70

5 0

3 years ago

A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

Oksanka [162]

Answer:

The null and alternative hypotheses are:

$H_{0}:\mu=75$

$H_{a} : \mu>75$

Under the null hypothesis, the test statistic is:

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }$

Where:

$\bar{x} =83$ is the sample mean

$s=9.8206$ is the sample standard deviation

$n=10$ is the sample size

$\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }$

$=2.58$

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

$t_{critical} =2.821$

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0

3 years ago