Dennis is a basketball fan. Dennis went to a Basketball Expo to buy and

Solve: 8 – 2x = 2 x= And how?

TiliK225 [7]

Answer:

x = 3

Step-by-step explanation:

8 - 2x = 2

- 2x = 2 - 8

- 2x = - 6

- x = - 6/2

- x = - 3

x = 3

5 0

3 years ago

Read 2 more answers

Arthur is interested in the effects of sleep deprivation usage on number of calories consumed. He asks a group of 20 college stu

Greeley [361]

Answer:

Arthur knows that there is a difference among the groups somewhere, but he does not know where

Step-by-step explanation:

An ANOVA test is a test to find out whether the results of an experiment or a survey are significant or not. ANOVA test helps the researcher or the experimenter to decide whether they reject the null hypothesis or accept the alternate hypothesis in the experiment. In ANOVA test, the experimenter wants to find if there is a difference between them or not.

In the context, Arthur is doing a study and he wishes to find out effect of a sleep deprivation on the number of the calories that people consumed. He collects some data from his subject group from the sleep lab and after running the ANOVA test, he finds out that he can reject the null hypothesis. So on this basis, Arthur knows that there is some basic difference among the members of the group somewhere, but he does not know where actually the difference is.

3 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

If the fdic has an insurance fund of 67.8 billion and must use 7.6% of it to cover several failed banks, approximately how much

erastovalidia [21]

If you're using 7.6 percent, then you're not using 92.4 percent (100-7.6)

To find 92.4 percent of 67.8 billion do:
67,800,000,000*.924=62,647,200,000

5 0

2 years ago

Read 2 more answers

A clothing store put a sales price of $48 on a purse. Before the markup, the store paid $40 for the purse. What percent markup d

Nimfa-mama [501]

Answer:

20% mark up

Step-by-step explanation:

[(48-40)/40]×100%= 20%

8 0

2 years ago