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Pepsi [2]
3 years ago
5

Put three number cards in a bag. ( 0 1 2 ) 2. Draw one card from the bag without looking. Put a mark in the tally column for the

number card. Put the card back into the bag. 3. Do this process for 20 times. Add the tally marks and write the number in the frequency column. Number Tally Frequency 0 1 2
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

X _____ tally ______ Frequency

0 _____ |||||_________ 5

1 ______|||||||| ________8

2 _____ ||||||| ________ 7

Step-by-step explanation:

Cards, x = 0, 1, 2

Constructing a table :

X _____ tally ______ Frequency

0 _____ |||||_________ 5

1 ______|||||||| ________8

2 _____ ||||||| ________ 7

Card 0 has a frequency of 5

Card 1 has a frequency of 8

Card 2 has a frequency of 7

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Henry spent 7 6/9 hours working on his reading and math homework.If he spent 6 7/8 on his reading homework,how much time did he
jeyben [28]
GCM of 8 and 9 is 72

6/9 = 64/72
7/8 = 63/72


1 1/72
6 0
3 years ago
Evan wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn, so he needs no fence
pentagon [3]

Answer:  A.   A=(1000-2w)*w      B. 250 feet

C.  125 000 square feet

Step-by-step explanation:

The area of rectangular is A=l*w    (1)

From another hand the length of the fence is 2*w+l=1000        (2)

L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.

Express l from (2):

l=1000-2w

Substitude l in (1) by 1000-2w

A=(1000-2w)*w        (3)   ( Part A. is done !)

Part B.

To find the width w  (Wmax) that corresponds to max of area A   we have to dind the roots of equation (1000-2w)w=0  ( we get it from (3))

w1=0  1000-2*w2=0

w2=500

Wmax= (w1+w2)/2=(0+500)/2=250 feet

The width that maximize area A is Wmax=250 feet

Part C.   Using (3) and the value of Wmax=250 we can write the following:

A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets

3 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,
tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let \bar X = <u><em>sample mean diameter</em></u>

The z score probability distribution for sample mean is given by;

                            Z  =  \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } }  ~ N(0,1)

where, \mu = population mean diameter = 141 millimetres

           \sigma = standard deviation = 7 millimetres

           n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P(\bar X > 141.4 millimetres)

      P(\bar X > 141.4) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } } > \frac{141.4-141}{\frac{7}{\sqrt{39} }  } } ) = P(Z > 0.36) = 1 - P(Z \leq 0.36)

                                                            = 1 - 0.6406 = <u>0.3594</u>

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0
3 years ago
Anyone know the answer?
kherson [118]

Answer:

A≈18.38

Step-by-step explanation:

Solve for area

Shape: Parallelogram

Formula: Base*Height

5.25*3.5=18.375

Round answer

Hope this helps.

6 0
3 years ago
A baker is using a cookie that calls for 2 1/4 cups of flour to yield 36 cookies, how much flour will the baker neeto to make 90
andre [41]

Answer:

5 \frac{5}{8} cups

Step-by-step explanation:

Given: A baker is using a cookie that calls for 2 \frac{1}{4} cups of flour to yield 36 cookies.

To find the number of flour will the baker need to make 90 cookies, we form a proportion.

Let's convert 2 \frac{1}{4} to improper fraction.

2\frac{1}{4} = \frac{(2*4) + 1}{4} = \frac{9}{4}

Let "x" be the amount flour to make 90 cookies

<u>Amount of Flour</u>                 <u>Number of cookies</u>

 \frac{9}{4}                               36

       x                                            90

Now form a proportion.

\frac{\frac{9}{4}}{x} = \frac{36}{90}

Now let's cross multiply, we get

\frac{9}{4} *90 = 36x\\\

\frac{810}{4} = 36x\\x = \frac{810 }{4*36} \\x = \frac{810}{144} \\\\x = 5 \frac{90}{144}

Now let's simplify the fraction part, Here the GCF of 90 and 144 is 18, so dividing the fraction's numerator and the denominator by 18, we get

x = 5 \frac{5}{8} cups

So the baker needs 5 \frac{5}{8} cups to make 90 cookies.

3 0
3 years ago
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