First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6
1 pound = 16 ounces so let's go ahead and convert 11 pounds to ounces by multiplying by 16. 11×16=176 and then add 13 to that 176+13=189
so 12 pounds and 13 ounces= 189 ounces
To solve this problem, we have to manually
solve for the value of x for each choices or equations. The correct equation
will give a value of -1 since the linear equations intersects at point (-1,
-4).
<span>1st: 7x + 3 = x + 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>2nd: 7x − 3 = x – 3</span>
7x – x = 3 – 3
6x = 0
<span>x = 0 (FALSE)</span>
<span>3rd: 7x + 3 = x − 3</span>
7x – x = - 3 – 3
6x = -6
<span>x = -1 (TRUE)</span>
<span>4th: 7x − 3 = x + 3</span>
7x – x = 3 + 3
6x = 6
<span>x = 1 (FALSE)</span>
Therefore the answer is:
<span>7x + 3 = x − 3</span>
Answer:
i need the answer too
Step-by-step explanation:
The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t
Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
brainly.com/question/26148784
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