The intersection can be parameterized by
with
.
By Stoke's theorem, the integral of
along
is equivalent to
where
is the region bounded by
. The line integral reduces to
Answer:
Exact Form:
72/5
Decimal Form:
14.4
Mixed Number Form:
14 2/5
Step-by-step explanation:
yea thats what i got
All you have to do is combine like terms here...all the x's and then all the constants. 2.3x + 2x -.2x = 4.1x; 14 + 15 = 29, so the perimeter is 4.1x + 29, A above.
F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
