Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
Answer:
BC ≈ 4.0
Step-by-step explanation:
∠ DCA = 180° - 70° = 110° ( adjacent angles )
∠ DAC = 180° - (30 + 110)° ← sum of angles in triangle
∠ DAC = 180° - 140° = 40°
Using the Sine rule in Δ ACD to find common side AC
= 
( cross- multiply )
AC × sin40° = 15 × sin30° ( divide both sides by sin40° )
AC = 
≈ 11.668
Using the cosine ratio in right triangle ABC
cos70° = 
= 
= 
( multiply both sides by 11.668 )
11.668 × cos70° = BC , then
BC ≈ 4.0 ( to the nearest tenth )
Step-by-step explanation:
First we need to find out what they all 3 equal, with multiplication.
5×5=25
10×5=50
20×5=100
In each of these problems, the answer is multiplying itself by 2 in order to get to the next answer. So this is how they are related
