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charle [14.2K]
3 years ago
13

The number of taxi accidents is approximated by y=−143.3x2+1823.3x+6820 and the number of injuries is approximated by y=−416.72x

^2+4416.7x+8500. Let x=0 represents​ 1990, x=1 represents​ 1991, and so on. According to the equation for the number of​ accidents, if the trend​ continued, how many taxi accidents occurred in 1998​?
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

To get for the taxi accidents in 1998, we must note that x = 8. Therefore using the equation y=−143.3x2+1823.3x+6820 , we can calculate for the number of taxi accidents.

y = -143.3 * (8)^2 + 1823.3 * 8 + 6820

y = 12,235.2

There were about 12,235 taxi accidents in 1998.

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Answer:

$7,000 at a rate of 7% and $21,000 at a rate of 14%.

Step-by-step explanation:

Let x be amount invested at 7% and y be amount invested at 14%.

We have been given that a women's professional organization made two small-business loans totaling $28,000. We can represent this information in an equation as:

x+y=28,000...(1)

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We are also told that the organization received from these loans was $3,430. We can represent this information in an equation as:

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Form equation (1), we will get:

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Upon substituting this value in equation (2), we will get:

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Therefore, an amount of $21,000 was invested at a rate of 14%.

x=28,000-y

x=28,000-21,000

x=7,000

Therefore, an amount of $7,000 was invested at a rate of 14%.

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