First we need to find x so 6x+8x+6x= 180
20x=180 and x= 9
So A= 6*9= 54
B= 8*9= 72
C= 6*9= 54
Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
Answer: 84 mm is MAYBE the answer.
area of square = 9 x 9 = 81 square feet
area of 1 corner = 1/2 * 3 * 3 = 4.5 square feet
4.5 * 4 = 18 square feet total of all 4 corners
81 - 18 = 63 square feet total not covered by benches.
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Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
