The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.
Given data:
The value of the first distance is, d1 = 0.25 m.
The value of the second distance is, d2 = 0.50 m.
The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,
v = d/t
Here,
d is the distance covered.
t is the average time taken to cover the distance.
Then the first velocity of the car at 0.25 m is,
v1 = d1/t1
v1 = 0.25 / t1
here, t1 is the average time for first distance.
And the second velocity of the car with four washers at the 0. 50 m mark is,
v2 = d2/t2
v2 = 0.50 /t2
here, t2 is the average time for the second distance.
Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.
Learn more about the velocity here:
brainly.com/question/862972
