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vredina [299]
3 years ago
7

HELPP !! pleaseeeeeeeee!!!!!!!!

Physics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:its the atomic symbol of magnesium.

Explanation:

sertanlavr [38]3 years ago
5 0

Answer:

Atomic name is your answer.

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While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p
algol13

Answer:

True

Explanation:

In Massachusetts it's illegal to drive while texting or on your phone.

3 0
4 years ago
A(n) is a line in which waves that are moving together are all in the same phase.
Ksivusya [100]
The line in which waves that are moving together are all in the same phase is referred to as the wave front. 
For example, in a series of waves, all of the crests that are in a single line make up a single wave front. This is the case for every set of particles at the same specific point in a series of waves.
5 0
3 years ago
A large object las Less of an attraction on a smaller <br><br> True <br> False
leva [86]
Do you mean ‘Does a larger object have less attraction than a smaller object?’ If so, then the answer is objects with a larger mass exert more attraction while objects with a smaller mass have less attraction.
6 0
3 years ago
A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some ins
Delvig [45]

Answer:

B= 1.14 X 10^{-7} Tesla

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

        B=\frac{I\mu}{2r\pi}

        B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}

      B= 1.14 X 10^{-7} Tesla

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

6 0
3 years ago
Calculate the frequencies corresponding to the wavelengths 500.00 nm and 500.10 nm. Use these to check the accuracy of equation
mel-nik [20]

Explanation:

It is given that,

Wavelength, \lambda_1=500\ nm=5\times 10^{-7}\ m

Wavelength, \lambda_2=500.10\ nm=5.001\times 10^{-7}\ m

We need to find the frequencies from corresponding wavelengths. The frequency of the light is given by :

f=\dfrac{c}{\lambda}  

c is the speed of light

Frequency 1,

f_1=\dfrac{c}{\lambda_1}  

f_1=\dfrac{3\times 10^8\ m/s}{5\times 10^{-7}\ m}  

f_1=6\times 10^{14}\ Hz

Frequency 2,

f_2=\dfrac{c}{\lambda_2}  

f_1=\dfrac{3\times 10^8\ m/s}{5.001\times 10^{-7}\ m}  

f_1=5.99\times 10^{14}\ Hz

Hence, this is the required solution.

3 0
3 years ago
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