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Ratling [72]
3 years ago
10

A block of wood has mass 4kg, what is the density of the wood if the mass of water is 3kg and its volume is half that of the blo

ck of the block of wood ?
Physics
1 answer:
mihalych1998 [28]3 years ago
7 0
M1(mass of wood) = 4 kg
M2(mass of water) = 3 kg
V1(volume of wood) = 2 * V2(volume of water )

Density = mass/volume ======= volume = mass/density
Density of water is 1 kg/m3
V2 = M2/density of water
V2 = 3 kg/m3/1kg/m3
V2 = 3 m3

V1(volume of wood) = 2 * V2
V1 = 2 * 3m3
V1 = 6m3

Density of wood = M1 ( mass of wood)/ V1(volume of wood)
Density of wood = 4 kg/ 6m3 = 2/3 kg/m3


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Which of the following is true of changes in momentum?
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Answer: ⇒  Answer is 3

<h2>Explanation: momentum = mass × velocity</h2>

"A small force may produce a large change in momentum by acting on a very massive object".

THEY HAVEN'T GIVEN US THE TIME PERIOD NOR THE DISTANCE TRAVELED. THEREFORE WE CANNOT ACTUALLY DECIDE IF THE FORCE IS KEPT FOR A LONG TIME OR SHORT TIME. ANYWAYS SINCE THE MASS IS GIVEN AS MASSIVE , THE  MOMENTUM SHOULD BE DEFINITELY HIGH.

WHY I SAY OTHERS ARE WRONG:

1) For a small force to give a large change in momentum, it should act for a long time interval.

2) By applying a large force for a short time interval, the change of momentum should be large.

3) Correct answer.

4) Acting over a short distance can be the same as acting over a short period of time.Therefore the distance should be large in order for a larger momentum.

I HOPE IT HELPS!

6 0
3 years ago
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shepuryov [24]

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8 0
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A toy gun uses a spring to project a 4.5-g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the gu
marishachu [46]

Answer:

1.93 m/s

Explanation:

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Spring constant = 8.0 N/m

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Compression = 5.8 cm = 0.058m

First, we find the P. E. stored in the spring:

P. E. = ½*k*x²

P. E. = ½ * 8 * 0.058² = 0.013J

Then, we find the work done by the frictional force while the sphere is leaving the barrel of the gun:

Work = Force * distance

The distance here is the length of the barrel.

Work = 0.035 * 0.13 = 0.0046 J

The kinetic energy of the sphere can now be found:

K. E. = P. E. - Work done

K. E. = 0.013 - 0.0046 = 0.0084J

We can now find the speed using the formula for K. E.:

K. E. = ½*m*v²

0.0084 = ½ * 0.0045 * v²

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4 0
3 years ago
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A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri
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Answer:

q=1\times10^{-8}C

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By use of Coulomb's law in electrostatics

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By substituting the values

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q=1\times10^{-8}C

Thus, the charge on the ball bearing is q=1\times10^{-8}C

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