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Ratling [72]
3 years ago
10

A block of wood has mass 4kg, what is the density of the wood if the mass of water is 3kg and its volume is half that of the blo

ck of the block of wood ?
Physics
1 answer:
mihalych1998 [28]3 years ago
7 0
M1(mass of wood) = 4 kg
M2(mass of water) = 3 kg
V1(volume of wood) = 2 * V2(volume of water )

Density = mass/volume ======= volume = mass/density
Density of water is 1 kg/m3
V2 = M2/density of water
V2 = 3 kg/m3/1kg/m3
V2 = 3 m3

V1(volume of wood) = 2 * V2
V1 = 2 * 3m3
V1 = 6m3

Density of wood = M1 ( mass of wood)/ V1(volume of wood)
Density of wood = 4 kg/ 6m3 = 2/3 kg/m3


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Answer:

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V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}

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d. The momentum of the 3 kg trolley is -12 kg·m/s

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Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

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The intensity I₂ of the light beam emerging from the second polarizer is zero.

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5 0
3 years ago
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