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Luden [163]
3 years ago
8

A student releases a ball from a height of 100 cm above the ground. It bounces to a height of 80 cm. Answer the following questi

ons according to the diagram

Physics
1 answer:
Zepler [3.9K]3 years ago
4 0

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

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the amplitude of the wave is which of the following A. Resonance B. Reflection C. Energy D. Magnitude
OLga [1]
D.Magnitude is the answer
8 0
3 years ago
PLEASE HELP WILL MAKE BRAINIEST (GIVING AWAY 20 POINTS)
Bond [772]

1) The most potential energy is at position A

2) The most kinetic energy is at position C

Explanation:

1)

The gravitational potential energy is the energy possessed by an object due to its position in a gravitational field, and it is given by the equation

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

From the equation, we see that the potential energy is directly proportional to the heigth of the object: therefore, the roller coaster in this problem will have the most potential energy at its highest postion, so at position A.

2)

The total mechanical energy of the roller coaster at any point along the track is given by

E=PE+KE

where

PE is the potential energy

KE is the kinetic energy

Assuming there is no friction, the mechanical energy E is constant. This means that when PE increases, KE decreases, and when PE increases, KE decreases.

Therefore, the cart will have maximum kinetic energy when the potential energy is at minimum: and since the potential energy is directly proportional to the height of the track, this will occur at the lowest position, so at position C.

Learn more about kinetic and potential energy:

brainly.com/question/6536722

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5 0
3 years ago
Question 1 of 10
Novay_Z [31]

Answer:

C. 5.6 × 10^11 N/C

Explanation:

The electric field E at a distance R from a charge Q is given by

E = k\dfrac{Q}{R^2}

where k = 9*10^9Nm/C is the coulomb's constant.

Now, in our case

R = 0.0075m

Q = 0.0035C;

therefore,

E = (9*10^9)\dfrac{0.0035C}{(0.0075m)^2}

\boxed{E = 5.6*10^{11}N/C.}

which is choice C from the options given<em> (at least it resembles it).</em>

6 0
3 years ago
A circular wire loop of radius 15.0 cm carries a current of 2.60
Korolek [52]
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm
5 0
3 years ago
Which layer lies between the stratosphere and the
Pepsi [2]
The answer is Mesosphere
8 0
3 years ago
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