The numerical value of the mean voltage is 25.47 V
To find the numerical value of the mean voltage, V of V(t) = 40 sin(t), we integrate V(t) with respect to t over the interval [0.π]
So,
![V = \frac{1}{\pi } \int\limits^\pi _0 {V(t)} \, dt \\V = \frac{1}{\pi } \int\limits^\pi _0 {40sint} \, dt \\V = \frac{1}{\pi } [-40cost]_{0}{\pi } \\V = \frac{1}{\pi } -[40cos\pi - 40cos0]\\\\V = \frac{1}{\pi } (-[40 X (-1) - 40 X 1})\\V = -\frac{1}{\pi } [-40 - 40]\\V = \frac{80}{\pi } \\V = 25.465 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7BV%28t%29%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7B40sint%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40cost%5D_%7B0%7D%7B%5Cpi%20%7D%20%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20-%5B40cos%5Cpi%20%20-%2040cos0%5D%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%28-%5B40%20X%20%28-1%29%20-%2040%20X%201%7D%29%5C%5CV%20%3D%20-%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40%20-%2040%5D%5C%5CV%20%3D%20%5Cfrac%7B80%7D%7B%5Cpi%20%7D%20%5C%5CV%20%3D%2025.465%20V)
V ≅ 25.47 V
So, the numerical value of the mean voltage is 25.47 V
Learn more about mean volatage here:
brainly.com/question/17928028
Answer:
y=3
(bc it is the same length as its perpendicular counterpart.
x= 9 (same with Z)
(From pythagorean theorem)
6^2+3^2= (root of) 45
and square root 45
and it is the same as its counterpart (which is z)
Step-by-step explanation:
as I explained on the answer(it doesnt let this part be unwritten)
It is 30 because u r dividing by 2 every time
Answer:
540
Step-by-step explanation:
