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3 years ago

Please help meeeee!!!!!!! complete the equation below. 5x+5x=10x____

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

5x5 - 10x = 0

5x5 - 10x = 5x • (x4 - 2)

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Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999

sp2606 [1]

Answer:

1 999 000

Step-by-step explanation:

Formula:

$1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right) }{2}$

………………………………………

Then

$1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right) }{2}$

$1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right) }{2}$

$1+2+3+....+1997+1998+1999=\frac{3998000 }{2}$

$1+2+3+....+1997+1998+1999=1999000$

7 0

1 year ago

12 Using side lengths only, could the triangles be similar? 0.5 m05 1 1.5

Murljashka [212]

Answer:

$\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}$

Step-by-step explanation:

$\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/$

$\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}$

$\text{Despite this, let's check the ratios}$

$\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5$

$\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}$

8 0

2 years ago

The ticket for ice hockey match was £14.50. the price has increased by 7%.

Serjik [45]

(14.50×7)/100 + 14.50

7 0

2 years ago

Read 2 more answers

Need help don't really get the question

marishachu [46]

Answer:

There are 24 squares

Step-by-step explanation:

By taking the small triangles and connecting them to make squares and adding those to the number of squares already there there are 24 squares in total.

8 0

2 years ago

4x²-5x+3 + 2x²+7x-8 a. 6x²+2x-5 b. 6x²+12x-5 c. 6x²-2x+5 d. 6x²+2x11

mrs_skeptik [129]

Combine the like terms

(4x^2 + 2x^2) +(7x - 5x) + (3 - 8)
6x^2 2x -5

6x^2 + 2x - 5

Answer is A

3 0

2 years ago