Answer:
4×3=12
answer=12
Step-by-step explanation:
2.5 is the diameter so you don't use that but
if you want the area it is 12
if you want the perimeter it
will be 3+3+4+4
Which is 6+8=14
Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...
126/42=378/126=1134/378=3
The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:
42=a(3)^(2-1)
42=3a
a=14
So the first term is 14.
Answer:
a)
degrees
b) 
Step-by-step explanation:
An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

a) Calculate I at (T ,H) = (95, 50).
degrees
(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.
This is the partial derivative of I in function of T, that is
. So



Answer:
1
Step-by-step explanation: