Answer:
(3, 1)
Step-by-step explanation:
Given the following constraints:
2x + 4y ≤ 10
x + 9y ≤ 12
x ≥ 0
y ≥ 0
We have to first graph the above constraints and secondly, we find the boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10 and x + 9y ≤ 12.
From the graph, the following points satisfy the constraints:
(0,0)
, (3,1)
, (0,4/3)
, (5,0)
Given that:
P = x + 6y
For (0, 0): P = x + 6y = 0 + 6(0) = 0
For (3, 1): P = x + 6y = 3 + 6(1) = 9
For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8
For (5, 0) P = x + 6y = 5 + 6(0) = 5
Answer:
a) 580 - 16n
b) 9850 - 271.72n
Step-by-step explanation:
a) starting number of bales = 580
each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day
After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is
original amount - amount lost = 580 - 16n
b)
First, we can calculate how much a bale weighs.
average = sum/count = 9850 kg / 580 ≈ 17 kg
Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be
starting - amount lost = 9850 - 271.72n
Answer:to find any geomtric shape draw like a solid box, if you can faltten it out and add diagrams,and labels
but volume is diffrent
Step-by-step explanation:
if helpful can you mark me brainest or give me a thanks
D,would be the correct answer.
