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sergeinik [125]
3 years ago
8

Solve (4 - x ≤ -1) ∩ (2 + 3x ≥ 17). Click on the graph until the solution set appears.

Mathematics
2 answers:
dlinn [17]3 years ago
8 0
Answer: I believe it’s “x is greater than or equal to 5.”
alex41 [277]3 years ago
5 0
Your answer is X is greater than 5
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for the linear function f, the graph of y=f(x) in the xy-plane passes through the points (0,2) and (9,9). what is the slope of y
Bas_tet [7]

Answer:

slope =  \frac{(y _{2} - y _{1})}{(x _{2}  - x _{1})}  \\  = \frac{(9 - 2)}{(9 - 0)}  \\  =  \frac{7}{9}  \\ hence \: slope \: is \:  \frac{7}{9}

5 0
3 years ago
Compare - 3.5 and - 3. Use &lt;, &gt;, or =.<br> -3.5 = -31<br> -3.5 &lt; - 3 -<br> -3.5&gt; -3
shusha [124]

Answer:

-3.5 < -3

Step-by-step explanation:

-3 is greater than -3.5

8 0
3 years ago
 Write a function with a zero of 1/2 . Explain how you know.
nalin [4]

Answer:

Simplest function is f(x) = 2x - 1

Step-by-step explanation:

When a function has a zero, simply put, that point is where the graph goes through the x-axis.  At this point, the y value is 0.

If a function has a 0 of 1/2, that translates to x = 1/2 and also (1/2, 0).  That means that y = 0 when x = 1/2.

If x = 1/2 and is a zero, then x - 1/2 = 0 and 2x - 1 = 0 (notice that y = 0 here and solving for x would get you right back to x = 1/2).

The simplest function with a zero of 1/2 is

f(x) = 2x - 1

You know it is true that the zero is 1/2 for two reasons.  First one is to set the right side equal to 0 and solve for x.

The second one is to graph the line y = 2x - 1 and see that it goes through the x axis at 1/2 where y = 0.

6 0
4 years ago
Please help!<br> Find the quadratic function with the roots of -2 and P
Marrrta [24]

The roots routine will return a column vector containing the roots of a polynomial. The general syntax is


  z = roots(p)


where p is a vector containing the coefficients of the polynomial ordered in descending powers.

Given a vector



which describes a polynomial




we construct the companion matrix (which has a characteristic polynomial matching the polynomial described by p), and then find the eigenvalues of it (which are the roots of its characteristic polynomial)



Example


Here is an example of finding the roots to the polynomial



--> roots([1 -6 -72 -27])



ans =  

  12.1229  

  -5.7345  

  -0.3884

3 0
3 years ago
Write the equation in standard form of the circle where center (-2,0) and radius 5​
DIA [1.3K]

Answer:

x²+y²+4x-21=0

Step-by-step explanation:

(x-h)²+(y-k)²=r²

(x--2)²+(y-0)²=(5)²

(x+2)²+y²=25

x²+4x+4+y²=25

x²+y²+4x-21=0

3 0
3 years ago
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