The Answer is:
(5a2-3a+8)+(-4a2-1)+(15a+11)
N; n+1; n+2 - 3 consecutive numbers
n(n + 1) = (n + 2)² - 19 |use a(b + c) = ab + ac and (a + b)² = a² + 2ab + b²
n² + n = n² + 4n + 4 - 19 |subtract n² from both sides
n = 4n - 15 |subtract 4n from both sides
-3n = -15 |divide both sides by (-3)
n = 5
n + 1 = 5 + 1 = 6
n + 2 = 5 + 2 = 7
Answer: 5; 6; 7.
Fifteen increased by a number
If you graph it, it looks linear.
Answer:
x^2 - 5x = 14
x^2 - 5x-14 = 0
Now, we have to find the multiples of -14 and numbers that add/subtract to -5; this helps to find the factors.
-7+2 = -5
-7*2 = -14
Based on the above info, we can find out my factors; they are:-
(x-7)(x+2)
