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alina1380 [7]
3 years ago
13

Look for a pattern in the data set to determine which kind of model best describes the data.

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0
If you graph it, it looks linear.
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How do I solve for the quadratic function?
Basile [38]
Aw you put the numbers in so a b c then you solve
3 0
2 years ago
What number is one hundred more than 792?
Andrej [43]
One hundred more than 792 = 792 + 100

792 + 100 = 892

892 is your answer

hope this helps
7 0
2 years ago
Read 2 more answers
Factorise the following.​
zepelin [54]

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

                = 9a²b²c²

8 0
2 years ago
A.Find the L.C.M of 18, 40, and 75.<br>​
Slav-nsk [51]

Answer:

1800

Step-by-step explanation:

→ First of all we need to find the prime factorisation of the numbers.

18 = 2 × 3 × 3 or 2 × 3²

40 = 2 × 2 × 2 × 5 or 2³ × 5

75 = 3 × 5 × 5 or 5² × 3

→ Now find the number that appear twice or more and write them down

3 and 3 from 18

2, 2 and 2 from 40

5 and 5 from 75

→ Now multiply all of these numbers together

3 × 3 × 2 × 2 × 2 × 5 × 5 = 3² × 2³ × 5² = 1800

5 0
2 years ago
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Which pair of complex factors results in a real number product? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)
photoshop1234 [79]

Answer:

(4 + 7i)(4 – 7i)

Step-by-step explanation:

This pair will produce a real answer because they are complex conjugates.

Complex conjugates ( a+bi) (a-bi)  when multiplied together form a real number ( a^2 + b^2)

6 0
3 years ago
Read 2 more answers
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