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3 years ago

8

There is a group of student,1/3 are in elementary ,1/2 are in middle school and 15 are in high school. How many are in the group

?

1 answer:

OverLord2011 [107]3 years ago

7 0

1/2 + 1/3 = 3/6 + 2/6 = 5/6
we have 5/6 so 15 is 1/6 of the entire group
15 × 6 = 90

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-2 2/3, -5 1/3, -10 2/3, -21 1/3, -42 2/3, ... Which formula can be use to describe the sequence?

Vesna [10]

D. f(x+1)=2f(x)

f(x+1)=2(-2 2/3)=-5 1/3
f(x+1)=2(-5 1/3)=-10 2/3
f(x+1)=2(-10 2/3)=-21 1/3
f(x+1)=2(-21 1/3)=-42 2/3

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3 years ago

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At Freddy’s fro yo shop 25 percent of the 44 frozen yogurt flavors are sugar free how many frozen yogurt flavors are sugar free

daser333 [38]

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2 years ago

Keith has $500 in his savings account at the beginning of the summer. He

bixtya [17]

Answer:

12

weeks

Explanation:

If Keith starts with

$

500

and wants to end with (at least)

$

200

he can withdraw up to

$

500

−

$

200

=

$

300

If he withdraws

$

25

week

the

$

300

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XXX

$

300

$

25

week

=

12

weeks

Step-by-step explanation:

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3 years ago

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Write an equation that passes through the points (0,-5) and (8,-5)

bezimeni [28]

Answer:

Equation of the line: $y = -5$ .

Step-by-step explanation:

Let $(x_0,\, y_0)$ and $(x_1,\, y_1)$ denote the coordinates of these two points, respectively.

Calculate the slope $m$ of this line:

$\displaystyle m = \frac{y_1 - y_0}{x_1 - x_0} = \frac{(-5) - (-5)}{8 - 0} = 0$ .

Notice that the slope is zero because the two points have the same $y$ -coordinates ( $y_0 = y_1 = -5$ ) even though their $x$ -coordinates are distinct ( $x_0 \ne x_1$ .)

Equation for this line in point-slope form:

$y - y_0 = m\, (x - x_0)$ .

$y - (-5) = 0\, (x - 0)$ .

Rewrite and simplify to obtain the equation of this line in slope-intercept form:

$y = -5$ .

The $x$ -term was eliminated because the slope was zero.

6 0

2 years ago

Can someone help me with the questions in the picture?

OverLord2011 [107]

Answer:

$y = 8$

Step-by-step explanation:

Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, $y - y_1 = m(x - x_1)$ and also in slope-intercept form, $y = mx + b$ .

Using a point, (-2, 8) and the slope (m), 0, substitute x1 = -2, y1 = 8 and m = 0 in $y - y_1 = m(x - x_1)$ .

Thus:

$y - 8 = 0(x - (-2))$

$y - 8 = 0$

Rewrite in slope-intercept form

$y - 8 + 8 = 0 + 8$ (addition property of equality)

$y = 8$

8 0

3 years ago