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Pachacha [2.7K]
3 years ago
10

A number is chosen at random from 1 to 25. Find the probability of selecting a number less than 2

Mathematics
1 answer:
grigory [225]3 years ago
3 0
It would be an 8% chance
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What is the slope of (9,6) (21,14)
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You would write m= y2 -y1/x2-x1 so the answer would be 8/12
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3 years ago
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Please help out and if you know help me show work ??
Ghella [55]

Answer:  14

<u>Step-by-step explanation:</u>

Consecutive even numbers would be {2, 4, 6, 8, 10, ...}

Let x represent the smallest number, then x + 2 is the middle number and x + 4 is the largest number.

1st number: x

2nd number: x + 2

3rd number: x + 4

1st number + 2nd number + 3rd number = Sum

      (x)        +      (x + 2)       +      (x + 4)      =  48

                                                      3x + 6   =  48

                                                      3x          = 42

                                                        x           = 14

1st number: x           ⇒ x = 14

2nd number: x + 2   ⇒ 14 + 2 = 16

3rd number: x + 4    ⇒ 14 + 4 = 18

<u>Check:</u>

14 + 16 + 18 = 48 \checkmark

 

7 0
3 years ago
Positionx (m)
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Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

v =  \frac{y1 - y2}{x1 - x2}

(y : position and x : time)

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t1 = 0s and t2 = 4s

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Step-by-step explanation:

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An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

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\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

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Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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