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Anni [7]
3 years ago
6

Find the value of x round to the nearest tenth

Mathematics
1 answer:
Alla [95]3 years ago
3 0

Answer:

Approximately 18.0.

Step-by-step explanation:

To find <em>x</em>, we can use the Law of Cosines.

The Law of Cosines is the following:

c^2=a^2+b^2-2ab\cos(C)

Now that the <em>c</em> is the side we're trying to find. Thus, the <em>c</em> is <em>x</em>. Also, Angle C is the angle opposite to <em>c</em> (or <em>x</em>). <em>a </em>and <em>b</em> are the two sides next to Angle C.

Plug in <em>x </em>for <em>c</em>, 16 for <em>a</em>, 30 for <em>b</em>, and 30 for Angle C:

x^2=(16)^2+(30)^2-2(16)(30)\cos(30)\\x^2=1156-960\cos(30)\\x=\sqrt{1156-960\cos(30)} \\x\approx18.0171

(Use a calculator. Make sure you're in degree mode!)

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Hey there,
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5 0
3 years ago
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

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→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

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3 years ago
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Step-by-step explanation:

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