In our school computer lab 10/20 of the computers have scanners. How is that written in simplest form?
1 answer:
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Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H
Now find the probability of flipping a head 4 times;
⁴
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Now find the probability of flipping a head 4 times;
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Answer:
The numbers are 38 and 57
Step-by-step explanation:
Let
x-----> the missing smaller number
y----> the missing larger number
we know that
-----> equation A
-----> equation B
substitute equation B in equation A and solve for y
Find the value of x