Question

Point C is located at (1, 2) and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D.
-0.25

3.25

-3.75

1.25

Answer 1

The answer is -0.25, When I graphed it that what I got.

Answer 2

Answer:

-0.25

Step-by-step explanation:

Coordinates of C  = $(x_{1} ,y_{1} )=(1,2)$

Coordinates of D =  $(x_{2} ,y_{2} )=(-4,-2)$

Let Coordinates of A= (x,y)

Since A point is located 1/4 the distance from C to D  

So the remaining distance from point A to D is 3/4

Thus the ratio of CA : AD = m:n=1:3

Now to find points of A we will use section formula i.e.

$x=\frac{mx_{2}+nx_{1}}{m+n}$

$y=\frac{my_{2}+ny_{1}}{m+n}$

Substituting the values:

$x=\frac{1*-4+3*1}{1+3}$

$x=\frac{-1}{4}$

$x=-0.25$

Thus Find the x value for the point that is 1 over 4 the distance from point C to point D is -0.25

Hence option a is correct