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Yanka [14]
3 years ago
11

Write and solve an equation to find the number n. Six times the sum of a number and 15 is -42.

Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

8

Step-by-step explanation:

6*(n + 15) = -42

Divide both sides by 6

6*(n - 15)/6 = -42/6

n - 15 = -7

n = -7 + 15

n = 8

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Sea World has 9 aquariums with small fish in them and the number of fish in each tank are shown below:45,10,48,19,36,25,63,14,37
zepelin [54]

Answer:

33

Step-by-step explanation:

Add all the numbers

Divide by 9

5 0
3 years ago
QF Q6.) Find the function for b.
Dimas [21]
The function notation f(x)=2x-4 means replace the x on the right-hand side with the value in parentheses on the left.
For example, f(y)=2y-4; f(4)=2(4)-4=4; f(1)=2(1)-4=-2 and so on.
The same principle applies to g(x), for example
g(2)=4(2^2)-3=13,
g(x+1)=4(x+1)^2-3=4(x^2+2x+1)-3=4x^2+8x+4-3=4x^2+8x+1
and so on.

(g of f)(x) is another way to write g(f(x)), therefore
g(f(x))
=g(2x-4)   [because f(x)=2x-4
=4(2x-4)^2-3
=4(4x^2-16x+16)-3
=16x^2-64x+64-3
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7 0
3 years ago
Read 2 more answers
Will the opposite of zero always, sometimes, o never zero
bija089 [108]
The opposite of zero (0) is -0, which is always equal to zero~
3 0
3 years ago
Alice and Bob share an allotment. The ratio of the area of Alice's
marusya05 [52]

Answer:

<h2>11:39</h2>

Step-by-step explanation:

Bob's portion of the allotment :

Total\:ratio=3+2 =5\\\\= \frac{2}{5}

Alice's portion :

Total\:ratio=3+2 =5\\\\= \frac{3}{5}

Vegetables are :

Total\:ratio=7+3 =10\\\\= \frac{7}{10} of the total area

Vegetables are :

Total\:ratio=4+1 =5\\\\= \frac{4}{5} of Alice's portion, or:

\frac{4}{5} \times(\frac{3}{5} ) = \frac{12}{25}

Bob's portion fraction (b):

\frac{12}{25}  + b = \frac{7}{10}

L.C.M of 25 and 10 =50

\frac{24}{50}  + b = \frac{35}{50} \\\\b =\frac{11}{50}\\\\ Ratio:\\50 - 11 = 39

Bob's vegetable to fruit ratio is 11 : 39

4 0
3 years ago
What is the solution of (x+4 over 2x-1)&lt;0
Nina [5.8K]

Answer:

x < 5

Step-by-step explanation:

Given that:

(x+4 over 2x-1)<0

It can be written as:

x + 4/2x-1 <0

Multiplying both sides by 2x -1

x+ 4 < 2x -1

By simplifying:

Take terms with x on left side and constants on right side:

x - 2x < -1 - 4

- x < -5

"-" sign will be cancelled from both sides

x < 5

i hope it will help You!

5 0
3 years ago
Read 2 more answers
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