<span>Its standard form of equation: (x-h)^2=-4p (y-k), (h,k)=(x,y) coordinates of the vertex
</span><span>For given parabola: Vertex = (-8, 2)
(x-(-8))</span>² = -4p(y - 2)
<span>solve for 4p using coordinates of given point ( -7, -1)
-7+8 = 4p (-1 - 2)
1 = 4p(-3)
4p = -1/3
So, Equation of given parabola:
(x+8)</span>² = -(y-2) / 3
Hope this helps!
Can someone help me on my stuff please
1 is PQR and RQP
2 is ABC and CBA
3 is STU and UTS
